[FIX] base, *: ensure name_search() returns lazy name_get() result

To avoid slowing down search like "{relational_field}" contains "{value}"
we always need to return the lazy name_get() for each [_]name_search method

closes odoo/odoo#36735

Signed-off-by: Raphael Collet (rco) <rco@openerp.com>

1 files changed, 3 insertions, 3 deletions

diff --git a/odoo/addons/test_impex/models.py b/odoo/addons/test_impex/models.py
index 353c8223f82..296c4677cc3 100644
--- a/odoo/addons/test_impex/models.py
+++ b/odoo/addons/test_impex/models.py
@@ -51,7 +51,7 @@ for name, field in MODELS:
         def _name_search(self, name, args=None, operator='ilike', limit=100, name_get_uid=None):
             if isinstance(name, str) and name.split(':')[0] == self._name:
                 record_ids = self._search([('value', operator, int(name.split(':')[1]))], access_rights_uid=name_get_uid)
-                return self.browse(record_ids).name_get()
+                return models.lazy_name_get(self.browse(record_ids).with_user(name_get_uid))
             else:
                 return []
 
@@ -72,7 +72,7 @@ class One2ManyChild(models.Model):
     def _name_search(self, name, args=None, operator='ilike', limit=100, name_get_uid=None):
         if isinstance(name, str) and name.split(':')[0] == self._name:
             record_ids = self._search([('value', operator, int(name.split(':')[1]))], access_rights_uid=name_get_uid)
-            return self.browse(record_ids).name_get()
+            return models.lazy_name_get(self.browse(record_ids).with_user(name_get_uid))
         else:
             return []
 
@@ -129,7 +129,7 @@ class Many2ManyChild(models.Model):
     def _name_search(self, name, args=None, operator='ilike', limit=100, name_get_uid=None):
         if isinstance(name, str) and name.split(':')[0] == self._name:
             record_ids = self._search([('value', operator, int(name.split(':')[1]))], access_rights_uid=name_get_uid)
-            return self.browse(record_ids).name_get()
+            return models.lazy_name_get(self.browse(record_ids).with_user(name_get_uid))
         else:
             return []